[SOLVED] Algebra2 Homework 5

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Problem 1. Write the following functions in the form f (x) = (x Β± h)2 Β± k by completing the square. Describe how x2 is shifted to obtain f(x). Graph f(x), label the vertex, label all axis intersections. An example of what I expect is given below.

(a) f(x)=x2+2xβˆ’1 (b) f(x)=x2 βˆ’7x+10

(c) f(x)=x2+x+1 (d) f(x)=x2 βˆ’8x+15 (e) f(x)=x2+3x

(f) f(x)=x2βˆ’4x+7 (g) f(x)=x2+23x+14 (h) f(x)=x2βˆ’xβˆ’1

(i) f(x)=x2+3x+17 36

Example. f(x) = x2 βˆ’ 2x βˆ’ 2

f(x)=x2 βˆ’2xβˆ’2

= (x2 βˆ’2x+(1)2 βˆ’(1)2)βˆ’2

= ((xβˆ’1)2 βˆ’1)βˆ’2

= (x βˆ’ 1)2 βˆ’ 3

Then f (x) = (x βˆ’ 1)2 βˆ’ 3 is the function x2 shifted right one unit, and shifted down 3 units. To find x-intercepts, we set f(x) = 0 and solve for x:

(xβˆ’1)2 βˆ’3=0 (xβˆ’1)2 =3

τ°“(x βˆ’ 1)2 = ±√3 √

Note that 1 + f (0):

√√ 3 is positive and 1 βˆ’

xβˆ’1=Β± 3 √

x=1Β± 3
3 is negative. To find the y-intercept, we set x = 0 and find

f(0)=(0βˆ’1)2 βˆ’3 = (βˆ’1)2 βˆ’ 3 =1βˆ’3
= βˆ’2

Note that if may have been easier to use the function as originally written to obtain this since

f(x)=x2 βˆ’2xβˆ’2 =β‡’ f(0)=02 βˆ’2(0)βˆ’2=βˆ’2

In any case we have f(0) = βˆ’2 so that our y-intercept is at y = βˆ’2. Be sure that all intercepts are labeled and that the vertex is indicated as in the graph below.

  • HW5-m080q8.zip