[SOLVED] STAT 292 Assignment 4  

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There are four questions, worth a total of 100 marks. Question 1 starts on page 2.

Assignment Guidelines (once more)

You are encouraged to discuss assignments with other students, but your submitted work must be your own.

The following Assignment Guidelines are helpful for all the assignments in Parts 2 and 3 of the course.

When you carry out a statistical test of hypothesis, you should state the following, when relevant:

  • Model equation.
  • Assumptions about the data, and comments about whether diagnostic graphs support those assumptions.
  • Null and alternative hypotheses.
  • ANOVA Table (if relevant), p-values.
  • Statistical conclusions. For example, “We reject H0 and conclude HA, that µ1 and µ2 differ at the 5% significance level”.
  • Interpretation of the statistical conclusions back to the original problem, using the original meaning of the response variable and any factors or covariates. For example, if comparing heights of two groups, “Female and male adults have different mean heights, with males being taller on average”.

Assignment Guidelines

1. Comprehension Test

Children in a school class are given a test of comprehension of English, marked out of 100. The children are from three different ethnic groups, which is thought to be an important factor. The question of interest is whether there are sex differences after allowing for ethnicity. The data follow:

  Females Males
Ethnic group E1 E2

E3

67 66 75 76 71 70 72 63 72 62 61 69 64 71 68 56
69 57 55 63 65 55 59 47 49
30 47 39 33
  • A two-way ANOVA was run on the data, with SAS output given on pages 3 to 6. Present the results from the ANOVA following the usual Assignment Guidelines, as given on page 1.
  • If a one-way ANOVA is done with factor Sex, the resulting ANOVA table is:
Source DF Sum of Squares Mean Square F value p-value
Sex 1 144.166 144.166 0.99 0.3292
Error 27 3942.662 146.025    
Total 28 4086.828      

Briefly discuss the outcomes of the separate tests for Sex presented in parts (a) and (b). Are the conclusions different? Give reasons to explain your answer.

                                        SAS Output for Comprehension Test

 

Linear Models 

 

The GLM Procedure

 

Class Level Information
Class Levels  Values
Ethnicity 3  E1 E2 E3
Sex 2  F M

 

Number of Observations Read  29
Number of Observations Used 29

 

 

Dependent Variable: Comprehension    

 

Source DF  Sum of Squares Mean Square  F Value Pr > F
Model 5     3365.438697 673.087739  21.46 <.0001
Error 23       721.388889 31.364734    
Corrected Total 28     4086.827586      

 

R-Square  Coeff Var  Root MSE Comprehension Mean
0.823484  9.275400  5.600423 60.37931

 

Source DF       Type I SS  Mean Square  F Value Pr > F
Ethnicity 2  3060.640086  1530.320043  48.79 <.0001
Sex 1  275.113176  275.113176      8.77 0.0070
Ethnicity*Sex 2     29.685435     14.842718      0.47 0.6289

 

 

 

                                        SAS Output for Comprehension Test

 

Linear Models 

 

The GLM Procedure

1

 

 

 

                                        SAS Output for Comprehension Test

 

 

 

 

                                        SAS Output for Comprehension Test

 

 

 

Note: E1 is the top line, E2 the middle line and E3 the lowest. (The lines are different colours, but that doesn’t show up if viewed or printed in black and white.)

2. Invertebrates in Mussel Clumps

The following data are from Peake and Quinn (1993), Temporal variation in speciesarea curves for invertebrates in clumps of an intertidal mussel, Ecography 16, 269277. The two variables used in this question are:

x = log10(Area) of each of 25 mussel clumps (in dm2), and

Y = number of different species of macroinvertebrates in each clump.

Note: Using log(Area) gives a straighter regression line than Area, which is why it is used. This is a transformation of x, not Y ; it has been done to improve linearity, not to stabilise variances.

The data follow. Decide if there is a useful linear relationship between x and Y , i.e. if x is a useful linear predictor of Y .

Clump logArea Species
1 2.71 3
2 2.67 7
3 2.66 6
4 2.97 8
5 3.13 10
6 3.25 9
7 3.23 10
8 3.25 11
9 3.49 16
10 3.60 9
11 3.65 13
12 3.65 14
13 3.70 12
14 3.65 14
15 3.74 20
16 3.87 22
17 3.85 15
18 3.96 20
19 4.01 22
20 3.97 21
21 4.14 15
22 4.31 24
23 4.39 25
24 4.43 25
25 4.42 24
  • A scatterplot of the data is given on page 8. Give comments on whether youthink the plot shows (i) linearity, (ii) constant variance.
  • Output from a simple linear regression using logArea to predict the numberof species is given on pages 9 and 10. Present a report on this analysis that includes (as usual) the model equation, hypotheses, assumptions, comments on whether the analysis is valid, plus statistical conclusions and interpretation.

                                         SAS Output for Mussel Clumps

 

 

Scatter Plot 

 

 

 

                                         SAS Output for Mussel Clumps

 

Linear Regression Results 

 

The REG Procedure

 

Model: Linear_Regression_Model

 

Dependent Variable: Species 

 

Number of Observations Read  25
Number of Observations Used 25

 

Analysis of Variance
Source DF Sum of

Squares

         Mean

      Square

 

 F Value

Pr > F
Model 1 868.50179  868.50179  117.85 <.0001
Error 23 169.49821     7.36949    
Corrected Total  24 1038.00000      

 

Root MSE 2.71468  R-Square  0.8367
Dependent Mean  15.00000  Adj R-Sq  0.8296
Coeff Var 18.09787    

 

Parameter Estimates
Variable DF Parameter

 Estimate

 Standard

       Error

 

 t Value

 Pr > |t|
Intercept  1  -25.64136  3.78287  -6.78  <.0001
logArea 1  11.20214  1.03189  10.86  <.0001

 

 

 

                                         SAS Output for Mussel Clumps

 

Linear Regression Results 

 

 

 

 

 

 

3. Coarse Woody Debris in Lakes

Christensen et al. (1996, Ecological Applications 6(4), 1143-1149) studied the relationships between coarse woody debris (CWD), shoreline vegetation and lake development in a sample of 16 lakes in North America. Coarse woody debris is useful in providing a habitat for various fish species. It is known to be related to the riparian (river-bank, lake-edge) tree density, irrespective of whether or not humans are present. The objective is to find out whether, after allowing for riparian tree density, human habitation is having an effect on the CWD.

The variables below were taken around the shoreline and near-shore water:

L10CABIN = log10 of 1 + density of cabins (number km−1),

RIP.DENS = density of riparian trees (trees km−1), and CWD.BASA = basal area of coarse woody debris (m2 km−1).

LAKE AREA RIP.DENS CWD.BASA L10CABIN
Bay 69 1270 121 0
Bergner 9 1210 41 0
Crampton 24 1800 183 0
Long 8 1875 130 0
Roach 20 1300 127 0
Tenderfoot 175 2150 134 0.20412
Palmer 254 1330 65 0.462398
Street 22 964 52 0.6627578
Laura 240 961 12 0.7075702
Annabelle 85 1400 46 0.763428
Joyce 12 1280 54 0.845098
Lake hills 25 976 97 0.8864907
Towanda 58 771 1 1.10721
Black oak 234 833 4 1.1238516
Johnson 31 883 1 1.2552725
Arrowhead 40 956 4 1.40824
  • Let Y = CWD.BASA, X1 = RIP.DENS and X2 = L10CABIN. Plots of Y X1, Y vs. X2 and X1 vs. X2 are given on page 12. Comment on any relationships you see.
  • SAS output for the following models is presented on pages 13 to 16. Diagnosticgraphs are shown for the last model.
  1. Regression of Y on the predictor X1 ii. Regression of Y on the predictor X2

iii. Regression of Y on the two predictors X1 and X2

For each analysis above, present the model equation, hypotheses and conclusions. For the third analysis, comment on whether or not the model assumptions are satisfied.

  • Which of the hypothesis tests from the three presented models gives the answerto the question of interest in this situation? Explain the answer.

L10CABIN                                                                                   RIP.DENS

L10CABIN

Scatterplots: CWD by L10CABIN, CWD by RIP.DENS, RIP.DENS by L10CABIN

                               Coarse Woody Debris        SAS Output

 

 

Linear Regression Results

The REG Procedure

 

Model: Linear_Regression_Model

 

Dependent Variable: CWD.BASA 

 

  Number of Observations Read 16  
  Number of Observations Used 16  
Analysis of Variance
Source DF Sum of Squares Mean Square F Value Pr > F
Model 1 32054 32054 24.30 0.0002
Error 14 18466 1318.96866    
Corrected Total  15 50520      
  Root MSE 36.31761 R-Square 0.6345  
  Dependent Mean 67.00000 Adj R-Sq 0.6084  
  Coeff Var 54.20539      
  Parameter Estimates  
  Variable DF Parameter Estimate Standard Error t Value Pr > |t|  
  Intercept 1 -77.09908 30.60801 -2.52 0.0246  
  RIP.DENS  1 0.11552 0.02343 4.93 0.0002  

 

Linear Regression Results

The REG Procedure

 

Model: Linear_Regression_Model

 

Dependent Variable: CWD.BASA 

 

  Number of Observations Read 16  
  Number of Observations Used 16  
Analysis of Variance
Source DF Sum of Squares Mean Square F Value Pr > F
Model 1 32840 32840 26.00 0.0002
Error 14 17680 1262.86950    
Corrected Total  15 50520      
  Root MSE 35.53688 R-Square 0.6500  
  Dependent Mean 67.00000 Adj R-Sq 0.6250  
  Coeff Var 53.04011      
  Parameter Estimates  
  Variable DF Parameter Estimate Standard Error t Value Pr > |t|  
  Intercept 1 121.96875 13.96871 8.73 <.0001  
  L10CABIN  1 -93.30142 18.29646 -5.10 0.0002  

 

 

 

Linear Regression Results

The REG Procedure

 

Model: Linear_Regression_Model

 

Dependent Variable: CWD.BASA 

 

  Number of Observations Read 16  
  Number of Observations Used 16  
Analysis of Variance
Source DF Sum of Squares Mean Square F Value Pr > F
Model 2 38041 19020 19.81 0.0001
Error 13 12479 959.93185    
Corrected Total  15 50520      
  Root MSE 30.98277 R-Square 0.7530  
  Dependent Mean 67.00000 Adj R-Sq 0.7150  
  Coeff Var 46.24294      
  Parameter Estimates  
  Variable DF Parameter Estimate Standard Error t Value Pr > |t|  
  Intercept 1 18.16485 46.22822 0.39 0.7007  
  RIP.DENS 1 0.06572 0.02823 2.33 0.0367  
  L10CABIN  1 -56.26481 22.53059 -2.50 0.0267  

 

 

 

 

4. Age of Teeth

In forensic work, scientists estimate the age of a skeleton by counting teeth cementum annulation (i.e. growth rings). Two teeth preparation methods, A and B, are compared by estimating the ages (Y ) of twenty teeth of known age (X). The teeth are randomly allocated to the two methods, ten to each, as follows.

Method A X = true age 49 13 38 55 44 56 7 66 18 39
  Y = estimated age 50 14 38 57 44 55 7 63 20 38
Method B X = true age 51 59 32 37 12 38 4 28 58 24
  Y = estimated age 51 59 29 34 10 35 5 25 57 22

A confirmatory analysis using a model with terms True Age (i.e. X), Method and True Age×Method is required.

  • Give the model equation for the required confirmatory analysis.
  • SAS output from a fitted model is given on pages 18 to 20. Present a report on this analysis that includes any necessary assumptions, comments on their validity, hypotheses, statistical conclusions at a 5% significance level, and interpretation plus discussion.

 

 

Linear Models

 

The GLM Procedure

 

Class Level Information
Class Levels  Values
Method            2 A B

 

Number of Observations Read  20
Number of Observations Used  20

 

 

Dependent Variable: Y    

 

Source DF  Sum of Squares Mean Square  F Value Pr > F
Model 3      6543.664660  2181.221553  946.16 <.0001
Error 16          36.885340        2.305334    
Corrected Total 19      6580.550000      

 

R-Square Coeff Var  Root MSE  Y Mean
0.994395 4.258997 1.518333 35.65000

 

Source DF        Type I SS  Mean Square  F Value Pr > F
X 1  6525.535206  6525.535206  2830.62 <.0001
Method 1     15.413619     15.413619        6.69 0.0199
X*Method 1        2.715836       2.715836        1.18 0.2938

 

Source DF      Type III SS  Mean Square  F Value Pr > F
X 1  6350.006837  6350.006837  2754.48 <.0001
Method 1     10.463729     10.463729        4.54 0.0490
X*Method 1        2.715836       2.715836        1.18 0.2938

 

 

 

 

 

Data and fitted lines: Method A line (dashed) is above Method B line (solid)

True age

  • Assignment-4-Linear-Regression-d960sh.zip