[SOLVED] Machine-Learning Homework 3

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1. Random Data Generator

a. Univariate gaussian data generator Input

Expectation value or mean:

Variance:
Output: A data point from

HINT

Generating values from normal distribution

You have to handcraft your geneartor based on one of the approaches given in the hyperlink.
You can use uniform distribution function (Numpy)

b. Polynomial basis linear model data generator is a vector

Input:

e.g. Output:

(basis number),

(a number) Internal constraint

,

is uniformly distributed.

2. Sequential Estimator

Sequential estimate the mean and variance

Data is given from the univariate gaussian data generator (1.a). Input: as in (1.a)

Function:

Call (1.a) to get a new data point from
Use sequential estimation to find the current estimates to and

Repeat steps above until the estimates converge.
Output: Print the new data point and the current estimiates of and in each iteration.

Notes

You should derive the recursive function of mean and variance based on the sequential esitmation.
Hint: Online algorithm

Sample input & output ( for reference only )

1 Datapointsourcefunction:N(3.0,5.0) 2

  1. 3  Adddatapoint:3.234685454257290
  2. 4  Mean = 3.408993960833291 Variance = 0.030383455464755956
  3. 5  Adddatapoint:0.519242879651157
  4. 6  Mean = 2.445743600439247 Variance = 1.875958150575018
  5. 7  Adddatapoint:1.347113997201991
  6. 8  Mean = 2.171086199629932 Variance = 1.633278676389248
  7. 9  Adddatapoint:8.979491998496083
  8. 10  Mean = 3.532767359403163 Variance = 8.723325264636875
  9. 11  Adddatapoint:3.603448448693051
  10. 12  Mean = 3.544547540951477 Variance = 7.270131583917285
  11. 13  Adddatapoint:4.127197937610908
  12. 14  Mean = 3.627783311902824 Variance = 6.273110519038578
  13. 15  Adddatapoint:4.992735798186870
  14. 16  Mean = 3.798402372688330 Variance = 5.692747751482052

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18 … 19

  1. 20  Adddatapoint:4.233592159021013
  2. 21  Mean = 2.961576104513964 Variance = 5.045715437349161
  3. 22  Adddatapoint:3.529990930040463
  4. 23  Mean = 2.961883688294010 Variance = 5.043159812425648
  5. 24  Adddatapoint:1.125210345431449
  6. 25  Mean = 2.960890354955524 Variance = 5.042255747918937

3. Baysian Linear regression

Input

The precision (i.e., b) for initial prior

All other required inputs for the polynomial basis linear model geneartor (1.b) Function

Call (1.b) to generate one data point
Update the prior, and calculate the parameters of predictive distribution Repeat steps above until the posterior probability converges.

Output

Print the new data point and the current paramters for posterior and predictive distribution.

After probability converged, do the visualization
Ground truth function (from linear model generator) Final predict result
At the time that have seen 10 data points
At the time that have seen 50 data points
Note

Except ground truth, you have to draw those data points which you have seen before

Draw a black line to represent the mean of function at each point Draw two red lines to represent the variance of function at each point

In other words, distance between red line and mean is ONE variance Hint: Online learning

Sample input & output (for reference only) 1. b=1,n=4,a=1,w=[1,2,3,4]

1 2 3 4 5 6 7

Add data point (-0.64152, 0.19039):

Postirior mean:
   0.0718294547
  -0.0460797888
   0.0295609502
  -0.0189638408

8

9 10 11 12

Posterior variance: 0.6227289276, 0.2420256620,

  -0.1552634839,

0.2420256620, -0.1552634839, 0.0996041049

0.8447365161, 0.0996041049, -0.0638976884

0.0996041049, 0.9361023116, 0.0409914289

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0.0996041049, -0.0638976884, 0.0409914289, 0.9737033172 Predictive distribution ~ N(0.00000, 2.65061)
Add data point (0.07122, 1.63175):

Postirior mean:
   0.6736864869
   0.2388980107
  -0.1054659080
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   0.0710615952

Posterior variance:

 0.3765992302,
 0.1254838660,
-0.1000441911,

0.1254838660, -0.1000441911, 0.0627881634

0.7895542671, 0.1257503020, -0.0813299447

0.1257503020, 0.9237138418, 0.0492510997

0.0627881634, -0.0813299447, 0.0492510997, 0.9681964094

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Predictive distribution ~ N(0.06869, 1.66008)

Add data point (-0.19330, 0.24507):

Postirior mean: 0.5760972313 0.2450231522 -0.0801842453 0.0504992402

Posterior variance:
0.2867129751, 0.1311255325, -0.0767580827, 0.0438488542 0.1311255325, 0.7892001707, 0.1242887609, -0.0801412282

-0.0767580827, 0.1242887609, 0.9176812972, 0.0541575540 0.0438488542, -0.0801412282, 0.0541575540, 0.9642058389

Predictive distribution ~ N(0.62305, 1.34848)

…

Add data point (-0.76990, -0.34768):

Postirior mean: 0.9107496675 1.9265499885 3.1119297129 4.1312375189

Posterior variance:
0.0051883836, -0.0004416700, -0.0086000319, 0.0008247001

-0.0004416700, 0.0401966605, 0.0012708906, -0.0554822477 -0.0086000319, 0.0012708906, 0.0265353911, -0.0031205875 0.0008247001, -0.0554822477, -0.0031205875, 0.0937197255

Predictive distribution ~ N(-0.61566, 1.00921)

Add data point (0.36500, 2.22705):

Postirior mean: 0.9107404583 1.9265225090 3.1119408740 4.1312734131

Posterior variance:
0.0051731092, -0.0004872471, -0.0085815201, 0.0008842340

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-0.0004872471, 0.0400606628, 0.0013261280, -0.0553046044

-0.0085815201, 0.0013261280, 0.0265129556, -0.0031927398

0.0008842340, -0.0553046044, -0.0031927398, 0.0934876838

Predictive distribution ~ N(2.22942, 1.00682)

2. b=100,n=4,a=1,w=[1,2,3,4]

1 (Consoleoutputomitted)

3. b=1,n=3,a=3,w=[1,2,3]

1 (Consoleoutputomitted)

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