Description
- Show that 𝐾8 can be drawn on a 2-holed torus without edges crossing. Feel free to use the octagon model as a framework for youre drawing:
- Use an edge-counting argument to show that 𝐾9 cannot be drawn on a
2-holed torus without edges crossing. Ingredients: For 𝐾9, you have
9
𝑛 = 9, 𝑚 = ( ) = 36. What would 𝑟 have to be? What is a lower 2
bound on the total edge count since every region must be bounded by at least three edges?
- If we re-orient the arcs around the diagram from #1 so they all point clockwise, what is the resulting value of 𝑛 − 𝑚 + 𝑟?
- In terms of 𝑛 ∈ {2,3,4,5,6, … }, how many tournaments are there with the node set 𝑁 = {1,2,3, … , 𝑛}? This is equivalent to asking for how many ways are there to orient the edges of 𝐾𝑛 with vertex set {1,2,3, … , 𝑛}.
- Let 𝑛 ∈ {3,4,5,6, … } be fixed. Show that there are exactly two orientations of 𝐶𝑛 with vertex set 𝑉 = {0,1,2, … , 𝑛 − 1} that are strongly connected.
